apakah kelompok bilangan 6,9 dan 11 adalah tripel pythagoras? buktikan
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Penyelesaian :
6,9,11
- a = 6
- b = 9
- c = 11
[tex] \sf \: {c}^{2} = {a}^{2} + {b}^{2} [/tex]
[tex] \sf \: \: {11}^{2} = {6}^{2} + {9}^{2} [/tex]
[tex] \sf \: 121 = 36 + 81[/tex]
[tex] \sf \: 121 ≠ 117[/tex]
jadi bilangan tersebut bukan termasuk tripel Pythagoras
[tex] \colorbox{violet}{ \tt\colorbox{ff0000}{}\colorbox{00ff00}{}\colorbox{00ffc0}{C}\colorbox{00ffff}{a}\colorbox{00c0ff}{l}\colorbox{0080ff}{l}\colorbox{0040ff}{M}\colorbox{0000ff}{}\colorbox{4000ff}{e}\colorbox{8000ff}{I}\colorbox{c000ff}{r}\colorbox{ff00ff}{i}\colorbox{ff00c0}{s}\colorbox{ff00a0}{h}\colorbox{ff0040}{}}[/tex]
Penjelasan dengan langkah-langkah:
11² > 6² + 9²
121 > 36 + 81
121 > 117
jadi, Bilangan tersebut bukan tryple pythagoras
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